Introductory Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-805-X
ISBN 13: 978-0-13417-805-9

Chapter 1 - Section 1.2 - Fractions in Algebra - Exercise Set - Page 31: 127

Answer

$a. \displaystyle \quad H=\frac{9}{10}(220-a)$ $b. \quad 162$ beats per minute.

Work Step by Step

$a.$ Based on the form of the formulas in previous exercises, we will subtract the age from 220, and multiply with the wanted factor of heart rate $H=\displaystyle \frac{9}{10}(220-a)$ $b.$ Substitute 40 for a $H=\displaystyle \frac{9}{10}(220-40)=\frac{9\cdot 180}{10}$ ... reduce the fraction with 10 $= \displaystyle \frac{9\cdot 18}{1}$ $=162$ beats per minute.
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