Linear Algebra and Its Applications (5th Edition)

Published by Pearson
ISBN 10: 032198238X
ISBN 13: 978-0-32198-238-4

Chapter 1 - Linear Equations in Linear Algebra - 1.8 Exercises - Page 69: 13

Answer

Vectors are rotated by $180^o$ around the origin $T(u)=\begin{bmatrix} -5\\ -2\\ \end{bmatrix}$ $T(v)=\begin{bmatrix} 2\\ -4\\ \end{bmatrix}$

Work Step by Step

$T(u)=\begin{bmatrix} -1 & 0\\ 0 & -1\\ \end{bmatrix}\begin{bmatrix} 5\\ 2\\ \end{bmatrix}=\begin{bmatrix} -5\\ -2\\ \end{bmatrix}$ $T(v)=\begin{bmatrix} -1 & 0\\ 0 & -1\\ \end{bmatrix}\begin{bmatrix} -2\\ 4\\ \end{bmatrix}=\begin{bmatrix} 2\\ -4\\ \end{bmatrix}$ Vectors graphed using Geogebra
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