Answer
The linear transformation projects the vectors onto the vertical y axis.
Work Step by Step
$T(u)=\begin{bmatrix} 0&0\\ 0&1\\ \end{bmatrix}\begin{bmatrix} 5\\ 2\\ \end{bmatrix}=\begin{bmatrix} 0\\ 2\\ \end{bmatrix}$
$T(v)=\begin{bmatrix} 0&0\\ 0&1\\ \end{bmatrix}\begin{bmatrix} -2\\ 4\\ \end{bmatrix}=\begin{bmatrix} 0\\ 4\\ \end{bmatrix}$
The linear transformation projects the vectors onto the vertical y axis.