Linear Algebra and Its Applications (5th Edition)

Published by Pearson
ISBN 10: 032198238X
ISBN 13: 978-0-32198-238-4

Chapter 1 - Linear Equations in Linear Algebra - Supplementary Exercises - Page 90: 4

Answer

See explanation

Work Step by Step

If matrix has pivot position in every column, then columns must be linearly independent. Because columns are linearly independent, system must have unique solution. Coefficient matrix with 3 pivot columns: $\left[\begin{array}{lll}* & - & - \\ 0 & * & - \\ 0 & 0 & *\end{array}\right]-\left[\begin{array}{l}- \\ - \\ -\end{array}\right]$ where asterix represents any nonzero number and - represents any number It is easy to see that solution is unique using back substitution to solve.
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