Answer
I will type matrices like this: (a b c/d e f), where (a b c) is the first row and (d e f) is the second row.
(2 -3/$\frac{-5}{2}$ 4)
Work Step by Step
I will type matrices like this: (a b c/d e f), where (a b c) is the first row and (d e f) is the second row.
This is a 2x2 matrix, therefore let A = (a b/ c d) if ad-bc $\ne$ 0.
Thus, $A^{-1}$ = $\frac{1}{ad-bc}$ $\times$ (d -b/-c a)
ad-bc = 8$\times$4 - 6$\times$5. Thus, ad-bc = 2
$A^{-1}$ = 1/2 $\times$ (4 -6/-5 8) which is (2 -3/$\frac{-5}{2}$ 4)
