Answer
(a) $C = 3.2 \times 10^{10} lb·mi^2$
(b) $W = 1280 lb.$
(c) Refer to the graph in the picture below
(d) No, but $W$ is very small when $x$ is large.
Work Step by Step
(a) $W = 2000lb$, $x = 4000mi$
$W = \frac{C}{x^2}$
$2000 = \frac{C}{(4000)^2}$, so $C = 3.2 \times 10^{10} lb·mi^2$
(b) $C = 3.2 \times 10^{10}$, $x = 5000$
$W = \frac{C}{x^2} = \frac{C}{5000^2} = \frac{(3.2 × 10^{10})}{(25 × 10^{6}
)} = 1280 lb.$
(c) No, but $W$ is very small when $x$ is large.
