Answer
(a) $y = sin(x + \frac{π}{2})$
(b) $y = 3 + 3 sin(\frac{2x}{9})$
(c) $y = 1 + 2 sin(2x − \frac{π}{2})$
Refer to the sketch in the picture below for more information
Work Step by Step
(a) $y_{0} = 0$, $A = 1$, $B = 1$ and $C = - \frac{\pi}{2}$
Hence the equation is $y = sin(x + \frac{π}{2})$
(b) $y_{0} = 3$, $A = 3$, $B = \frac{2}{9}$ and $C = 0$
Hence the equation is $y = 3 + 3 sin(\frac{2x}{9})$
Refer to the sketch in the picture below for more information
(c) $y_{0} = 1$, $A = 2$, $B = 2$ and $C = \frac{\pi}{2}$
Hence the equation is $y = 1 + 2 sin(2x − \frac{π}{2})$
