Calculus, 10th Edition (Anton)

Published by Wiley
ISBN 10: 0-47064-772-8
ISBN 13: 978-0-47064-772-1

Chapter 0 - Before Calculus - 0.3 Families Of Function - Exercises Set 0.3 - Page 37: 26

Answer

True

Work Step by Step

We can rewrite the curve: $y=x^2 + bx + c = (x+\frac{b}{2})^2 + (c-\frac{b^2}{4})$. We can achieve this curve by translating $y=x^2$ to the left by $\frac{b}{2}$ units to reach $y = (x+\frac{b}{2})^2$. We then translate $y = (x+\frac{b}{2})^2$ upwards by $(c-\frac{b^2}{4})$ to reach $y=(x+\frac{b}{2})^2 + (c-\frac{b^2}{4})$. This, as shown above, is equal to $y = x^2 + bx + c$. Thus, each curve in the family $y=x^2 + bx + c$ is a translation of the graph $y=x^2$.
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