Calculus 10th Edition

Published by Brooks Cole
ISBN 10: 1-28505-709-0
ISBN 13: 978-1-28505-709-5

Chapter 1 - Limits and Their Properties - 1.3 Exercises - Page 69: 106

Answer

$\lim\limits_{x\to c} g(x)$ does not exist.

Work Step by Step

The limit property suggests that $\lim\limits_{x \to c}[f(x)+g(x)]=\lim\limits_{x\to c} f(x)+\lim\limits_{x\to c} g(x)$ Let us assume that the limit $\lim\limits_{x\to c} f(x)$ exists. Consider $\lim\limits_{x\to c} g(x)=P$ and so, $\lim\limits_{x \to c}[f(x)+g(x)]=Q$ Now, $Q=\lim\limits_{x\to c} f(x)+\lim\limits_{x\to c} g(x) \implies Q=\lim\limits_{x\to c} f(x)+P$ This implies that $\lim\limits_{x\to c} f(x)=Q-P$, that is, the limit exists. Hence, the limit $\lim\limits_{x\to c} g(x)$ does not exist.
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