Answer
$\lim\limits_{x\to\frac{1}{2}^+}\dfrac{x}{2x-1}=+\infty.$
Work Step by Step
$\lim\limits_{x\to\frac{1}{2}^+}\dfrac{x}{2x-1}=\dfrac{(\frac{1}{2}^+)}{2(\frac{1}{2}^+)-1}=\dfrac{\frac{1}{2}}{0^+}=+\infty.$
Calculus 10th Edition
by Larson, Ron; Edwards, Bruce H.
Published by
Brooks Cole
ISBN 10:
1-28505-709-0
ISBN 13:
978-1-28505-709-5
Chapter 1 - Limits and Their Properties - Review Exercises - Page 92: 74
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