Answer
$\lim\limits_{x\to0^-}\dfrac{\cos^2{x}}{x}=-\infty.$
Work Step by Step
$\lim\limits_{x\to0^-}\dfrac{\cos^2{x}}{x}=\dfrac{\cos^2{0^-}}{0^-}=\dfrac{1}{0^-}=-\infty.$
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