Answer
(a) $f(-3)=4$
(b) $f(1)=0$
(c) $f(3)=-2$
(d) $f(b^2+1)=-b^2$
Domain: All real numbers
Range: $(-\infty,0]∪[1,\infty)$
Work Step by Step
(a)
$f(-3)=|-3|+1$, since $-3<1$
$f(-3)=4$
(b)
$f(1)=-(1)+1$, since $1\geq1$
$f(1)=0$
(c)
$f(3)=-(3)+1$, since $3\geq1$
$f(3)=-2$
(d)
$f(b^2+1)=-(b^2+1)+1$, since $b^2+1\geq1$
$f(b^2+1)=-b^2$
Domain: All real numbers
Range: $(-\infty,0]∪[1,\infty)$
