Answer
A: $ f(\pi)= 0 $
B: $ f(\frac{5\pi}{4})=-\frac{\sqrt{2}}{2} $
C: $ f(\frac{2\pi}{3})=\frac{\sqrt{3}}{2} $
D: $ f(-\frac{\pi}{6})=-\frac{1}{2} $
Work Step by Step
A:
$ f(\pi)= \sin{\pi} $
$ f(\pi)= 0 $
B:
$ f(\frac{5\pi}{4})= \sin{\frac{5\pi}{4}} $
$ f(\frac{5\pi}{4})=-\frac{\sqrt{2}}{2} $
C:
$ f(\frac{2\pi}{3})= \sin{\frac{2\pi}{3}} $
$ f(\frac{2\pi}{3})=\frac{\sqrt{3}}{2} $
D:
$ f(-\frac{\pi}{6})=\sin{(-\frac{\pi}{6})} $
$ f(-\frac{\pi}{6})=-\frac{1}{2} $
