Chapter P - P.3 - Linear Models and Rates of Change - Exercises - Page 30: 96

a) see image of graph b) $H(\frac{x}{1.6})=0.00078125x^2+0.003125x-0.029$

a) the function was graohed using graphing softare. b) $H(\frac{x}{1.6})=0.002(\frac{x}{1.6})^{2}+0.005(\frac{x}{1.6})-0.029$ $H(\frac{x}{1.6})=\frac{0.002x^{2}}{2.56}+(\frac{0.005x}{1.6})-0.029$ $H(\frac{x}{1.6})=0.00078125x^2+0.003125x-0.029$