Calculus (3rd Edition)

Published by W. H. Freeman
ISBN 10: 1464125260
ISBN 13: 978-1-46412-526-3

Chapter 1 - Precalculus Review - 1.1 Real Numbers, Functions, and Graphs - Exercises - Page 10: 36

Answer

1) d = $2\sqrt 2$ 2) d = $3$ 3) d = $\sqrt {13} $ 4) d = $ \sqrt {37} $

Work Step by Step

The distance between point (x_{1}, y_{1}) and the point (x_{2}, y_{2}) is: $d = \sqrt {(x_2-x_1)^{2}+(y_2-y_1)^{2}} $ 1) Points (1,4) and (3,2): $d = \sqrt {(3-1)^{2}+(2-4)^{2}} $ $ d= 2\sqrt2 $ 2) Points (2,4) and (2,1): $d = \sqrt {(2-2)^{2}+(1-4)^{2}} $ $ d= 3 $ 3) Points (-2,3) and (0,0): $d = \sqrt {(0-(-2))^{2}+(0-3)^{2}} $ $ d= \sqrt{13} $ 4) Points (-2,3) and (-3,-3): $d = \sqrt {(-3-(-2))^{2}+(-3-3)^{2}} $ $ d= \sqrt{37} $
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