Calculus (3rd Edition)

Published by W. H. Freeman
ISBN 10: 1464125260
ISBN 13: 978-1-46412-526-3

Chapter 1 - Precalculus Review - 1.1 Real Numbers, Functions, and Graphs - Exercises - Page 10: 49

Answer

$f$ is increasing on (-1,$\infty$)

Work Step by Step

Define $f(x) = | x+1 |$ as two separate cases, When $x\leq -1$, $f(x) = -(x+1)$ $\implies$ $f'(x) = -1$, which means $f$ is decreasing When $x>-1$, $f(x) = x+1$ $\implies$ $f'(x) = 1$, which means $f$ is increasing
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