Calculus (3rd Edition)

Published by W. H. Freeman
ISBN 10: 1464125260
ISBN 13: 978-1-46412-526-3

Chapter 1 - Precalculus Review - 1.1 Real Numbers, Functions, and Graphs - Exercises - Page 10: 52

Answer

$(-\infty,0)$.

Work Step by Step

For the function $f(x)=\frac{1}{x^4+x^2+1}$, we note that the denominator is positive for all values of $x$. Since the decreasing of the absolute value of x make the denominator decrease, the function $f(x)$ is increasing. So the function in increasing on the interval $(-\infty,0)$.
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