Answer
See the proof below.
Work Step by Step
We have
$$|f (x) − 3| = |3 − 3| = 0$$ for all $ x $, so when we make $ x $ sufficiently close to $3$, the result is sufficiently close to $0$. Hence, $$\lim_{x\rightarrow 5}3=3.$$
Calculus (3rd Edition)
by Rogawski, Jon; Adams, Colin
Published by
W. H. Freeman
ISBN 10:
1464125260
ISBN 13:
978-1-46412-526-3
Chapter 2 - Limits - 2.2 Limits: A Numerical and Graphical Approach - Exercises - Page 54: 10
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