Answer
$\frac{5}{3}.$
Work Step by Step
We have $$
\lim _{x \rightarrow 2} \frac{x^{2}+x-6}{x^{2}-x-2}=
\lim _{x \rightarrow 2} \frac{(x+3)(x-2)}{(x-2)(x+1)}=\lim _{x \rightarrow 2} \frac{x+3}{x+1}=\frac{5}{3}.
$$
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