Answer
8
Work Step by Step
$\lim\limits_{x \to 2} x\sqrt {20-x^{2}} $ = $2\sqrt {20-2^{2}} $
$\lim\limits_{x \to 2} x\sqrt {20-x^{2}} $ = $2 (\sqrt 16) = 2(4) $
$\lim\limits_{x \to 2} x\sqrt {20-x^{2}} $ = $8$
Calculus 8th Edition
by Stewart, James
Published by
Cengage
ISBN 10:
1285740629
ISBN 13:
978-1-28574-062-1
Chapter 1 - Functions and Limits - 1.8 Continuity - 1.8 Exercises - Page 92: 35
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