Calculus 8th Edition

Published by Cengage
ISBN 10: 1285740629
ISBN 13: 978-1-28574-062-1

Chapter 1 - Functions and Limits - 1.8 Continuity - 1.8 Exercises - Page 92: 36

Answer

0

Work Step by Step

x and sin x are continuous, thus sin (x + sin x) is continuous $\lim\limits_{x \to \pi} sin (x+sin x)$ = $ sin(\pi + sin \pi) $ $\lim\limits_{x \to 2} sin (x+sin x) $ = $ sin(\pi + 0) $ $\lim\limits_{x \to 2} sin (x+sin x)$ = $ sin(\pi) $ $\lim\limits_{x \to 2}sin (x+sin x)$ = $ 0 $
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