Multivariable Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 0-53849-787-4
ISBN 13: 978-0-53849-787-9

Chapter 10 - Parametric Equations and Polar Coordinates - 10.6 Exercises - Page 708: 3

Answer

$$r = \frac 6 {2 + 3 \space sin(\theta)}$$

Work Step by Step

1. Determine the equation that we are going to use: Since the directrix is defined by $y = 2$, we are going to use $sin(\theta)$ in the formula. Since $2$ is positive, the equation will have "$+sin(\theta)$": $$r = \frac{ed}{1 + esin(\theta)}$$ 2. Substitute the given values for $d$ (directrix) and e (eccentricity): $$r = \frac{(1.5)(2)}{1 + (1.5)sin(\theta)} = \frac{3}{1 + 1.5\space sin(\theta)}$$ If we want to remove the decimal number, we should multiply the fraction by $\frac 2 2$: $$r = \frac{3}{1 + 1.5\space sin(\theta)} \times \frac 22 = \frac 6 {2 + 3 \space sin(\theta)}$$
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