Multivariable Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 0-53849-787-4
ISBN 13: 978-0-53849-787-9

Chapter 10 - Parametric Equations and Polar Coordinates - 10.6 Exercises - Page 708: 5

Answer

$$ r = \frac 8 {1 - sin(\theta)}$$

Work Step by Step

1. Determine the equation that we are going to use: The vertex is at $(4, \frac{3\pi}{2})$ The angle $(\frac {3\pi} 2)$ indicates that the directrix is a horizontal line below the x-axis. $(y = -c)$ If we multiply 4 by 2, we will get the absolute value of $c$, which is 8. Directrix: $y = -8$ Thus, we are going to use $sin(\theta)$ in the formula. Since $-8$ is negative, the equation will have "$-sin(\theta)$": $$r = \frac{ed}{1 - esin(\theta)}$$ 2. Substitute the given values for $d$ (directrix) and e (eccentricity): ** Parabolas: e = 1 ** d = 8 (absolute value) $$r = \frac{(1)(8)}{1 - (1)sin(\theta)} = \frac 8 {1 - sin(\theta)}$$
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