Answer
$18$
Work Step by Step
Given: $r^2=9 cos 5 \theta$
$Area,A=\int_{- \pi/10}^{\pi/10}\frac{r^2}{2}d\theta$
$=\int_{- \pi/10}^{\pi/10}\dfrac{9cos5 \theta}{2}d\theta$
$=10[\dfrac{9sin5 \theta}{10}]_{- \pi/10}^{\pi/10}$
$=18$
Multivariable Calculus, 7th Edition
by Stewart, James
Published by
Brooks Cole
ISBN 10:
0-53849-787-4
ISBN 13:
978-0-53849-787-9
Chapter 10 - Parametric Equations and Polar Coordinates - Review - Exercises - Page 710: 31
Update this answer!
You can help us out by revising, improving and updating this answer.
Update this answerAfter you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.
