Answer
Even
Work Step by Step
Given $ f(a-x)=f(a+x)$ and $ g(x)=f(x+a)$, we have
$ g(-x)=f(a-x)=f(x+a)=g(x)$. Hence $ g(x)$ is an even function.
Thomas' Calculus 13th Edition
by Thomas Jr., George B.
Published by
Pearson
ISBN 10:
0-32187-896-5
ISBN 13:
978-0-32187-896-0
Chapter 1: Functions - Practice Exercises - Page 37: 18
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