Thomas' Calculus 13th Edition

Published by Pearson
ISBN 10: 0-32187-896-5
ISBN 13: 978-0-32187-896-0

Chapter 1: Functions - Practice Exercises - Page 37: 37

Answer

(a). $-x $, $[-2,\infty)$, $(-\infty, 2]$ (b). $\sqrt {4-x^2}$, $[-2,2]$, $[0, 2]$

Work Step by Step

(a). $ f(g(x))=2-(x+2)=-x $ Domain: $[-2,\infty)$ Range: $(-\infty, 2]$ (b). $ g(f(x))=\sqrt {2-x^2+2}=\sqrt {4-x^2}$ Domain: $[-2,2]$ Range: $[0, 2]$
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