Thomas' Calculus 13th Edition

Published by Pearson
ISBN 10: 0-32187-896-5
ISBN 13: 978-0-32187-896-0

Chapter 2: Limits and Continuity - Section 2.1 - Rates of Change and Tangents to Curves - Exercises 2.1 - Page 46: 2

Answer

a.)2 b.)0

Work Step by Step

The average rate of change of y = f(x) with respect to x over the interval [x1,x2] is: $\frac{f(x2) - f(x1)}{x2-x1}$. a.) g(x) = $x^{2}$ - 2x Interval = [1,3] $\frac{g(3) - g(1)}{3-1}$. g(3) = $x^{2}$ -2x = $3^{2}$ -2.3 = 9-6 = 3 g(1) = $x^{2}$ -2x = $1^{2}$ -2.1= 1-2= -1 $\frac{3 - (-1)}{3-1}$. = $\frac{4}{2}$ = 2 b.)Interval = [-2, 4] $\frac{g(4) - g(-2)}{4-(-2)}$. g(4) = $x^{2}$ -2x = $4^{2}$ -2.4 = 16-8= 8 g(1) = $x^{2}$ -2x = $(-2)^{2}$ -2.(-2)= 4+4= 8 $\frac{8 - (8)}{4-(-2)}$. = $\frac{0}{6}$ = 0
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