Answer
a. $4$
b. $ y=4x-9$
Work Step by Step
Given $ y=x^2-5, P(2,-1)$
a. Slope=$\frac{(2+h)^2-2^2}{h}=\frac{4h+h^2}{h}=4+h=4$ (as h approach zero)
b. tangent line at P: $ y+1=4(x-2)$, which gives $ y=4x-9$
Thomas' Calculus 13th Edition
by Thomas Jr., George B.
Published by
Pearson
ISBN 10:
0-32187-896-5
ISBN 13:
978-0-32187-896-0
Chapter 2: Limits and Continuity - Section 2.1 - Rates of Change and Tangents to Curves - Exercises 2.1 - Page 46: 7
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