Answer
a. False. Every circle is not to the right of every triangle. For instance, circle b is not to the right of triangle c.
b. Formal: (($\forall x$ Circle(x) $\land \forall y$ Triangle(y))$\rightarrow$ RightOf(x, y))
c. Negation: ((($\exists x$ Circle(x) $\lor \exists y$ Triangle(y)) $\land$ ~RightOf(x, y)))
Work Step by Step
c. ~((($\forall x$ Circle(x) $\land \forall y$ Triangle(y))$\rightarrow$ RightOf(x, y)))
$\equiv$ ((($\exists x$ Circle(x) $\lor \exists y$ Triangle(y)) ~$(\rightarrow$ RightOf(x, y))))
(by De Morgan's Law and the law of negating $\forall$ statement)
$\equiv$ ((($\exists x$ Circle(x) $\lor \exists y$ Triangle(y)) $\land$ ~RightOf(x, y)))
(by the law of negating an if-then statement)
