Discrete Mathematics with Applications 4th Edition

Published by Cengage Learning
ISBN 10: 0-49539-132-8
ISBN 13: 978-0-49539-132-6

Chapter 3 - The Logic of Quantified Statements - Exercise Set 3.4 - Page 143: 10

Answer

Valid by universal modus tollens.

Work Step by Step

Universal modus tollens: $\forall x, $ if $P(x)$ then $Q(x)$. ~$Q(a)$ for a particular $a$. ~$\therefore P(a)$. In this case P(x) is: the product of two numbers is 0. Q(x) is: at least one of the numbers is 0. a are the particular two numbers (2x+1) and (x-7) for some number x.
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