Answer
Invalid by the converse error.
Work Step by Step
Converse Error: $\forall x$ if $P(x)$ then $Q(x)$.
$Q(a)$ for a particular $a$.
$\therefore P(a)$. (invalid conclusion)
In this case P(x) is: x is even.
Q(x) is: 2x is even.
a is n.
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