Answer
(a) $(-1,1)$, $\sqrt 2$. (b) see graph. (c) $(0,0),(-2,0)$, $(0,2)$,
Work Step by Step
(a) Given $3(x+1)^2+3(y-1)^2=6$ or $(x+1)^2+(y-1)^2=2$, we can identify its center $(h,k)=(-1,1)$ and radius $r=\sqrt 2$.
(b) see graph.
(c) We can find the x-intercepts $(0,0),(-2,0)$ and y-intercepts $(0,0),(0,2)$
