Precalculus (10th Edition)

Published by Pearson
ISBN 10: 0-32197-907-9
ISBN 13: 978-0-32197-907-0

Chapter 1 - Graphs - 1.4 Circles - 1.4 Assess Your Understanding - Page 38: 9

Answer

equation in standard form: $(x-2)^2+(y-1)^2=4$ center: $(2, 1)$ radius = $2$ units

Work Step by Step

The standard equation for a circle with radius $r$ and centre $(h,k)$ is: $(x-h)^2+(y-k)^2=r^2$. The distance between the point on the circle $(0, 1)$ and the center $(2, 1)$ is $2$ units. The given circle has $r=2$ and has its center at $(2, 1)$. Thus, the standard form of the circle's equation is: $(x-2)^2+(y-1)^2=2^2\\ (x-2)^2+(y-1)^2-4$
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