Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter R - Review of Basic Concepts - R.5 Rational Expressions - R.5 Exercises - Page 54: 71

Answer

$\dfrac{x+1}{x-1}$

Work Step by Step

Simplify by multiplying the LCD (which is $x$) to both the numerator and the denominator to obtain: $=\dfrac{x(1+\frac{1}{x})}{x(1-\frac{1}{x})} \\=\dfrac{x(1)+x(\frac{1}{x})}{x(1)-x(\frac{1}{x})} \\=\dfrac{x+1}{x-1}$
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