Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter R - Review of Basic Concepts - R.5 Rational Expressions - R.5 Exercises - Page 54: 86

Answer

$\frac{2}{x(x+h)}$

Work Step by Step

Step 1. Perform operations to the numerator: $\frac{-2}{x+h}-\frac{-2}{x}=\frac{-2x+2x+2h}{x(x+h)}=\frac{2h}{x(x+h)}$ Step 2. Use the above results in the original expression, we have: $\frac{\frac{-2}{x+h}-\frac{-2}{x}}{h}=\frac{\frac{2h}{x(x+h)}}{h}=\frac{2}{x(x+h)}$
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