Answer
$\frac{6}{m^{1/4}n^{3/4}}$
Work Step by Step
$(\frac{16m^3}{n})^{1/4}(\frac{9n^{-1}}{m^2})^{1/2}=(\frac{2^4m^3}{n})^{1/4}(\frac{3^2}{m^2n})^{1/2}=2\cdot3(\frac{m^{3/4}}{n^{1/4}})(\frac{1}{mn^{1/2}})=\frac{6}{m^{1/4}n^{3/4}}$
Precalculus (6th Edition)
by Lial, Margaret L.; Hornsby, John; Schneider, David I.; Daniels, Callie
Published by
Pearson
ISBN 10:
013421742X
ISBN 13:
978-0-13421-742-0
Chapter R - Review of Basic Concepts - R.6 Rational Exponents - R.6 Exercises - Page 64: 75
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