Answer
$\color{blue}{-4k^{10/3} + 24k^{4/3}}$
Work Step by Step
RECALL:
(1) $a(b+c) = ab + ac$
(2) $a^m \cdot a^n = a^{m+n}$
Use rule (1) above to obtain:
$=-4k \cdot k^{7/3} - (-4k) \cdot 6k^{1/3}
\\=-4k \cdot k^{7/3} +4k\cdot 6k^{1/3}$
Use rule (2) above to obtain:
$=-4k^{1+(7/3)} + 24k^{1+(1/3)}
\\=-4k^{3/3+7/3} + 24k^{3/3+1/3}
\\=\color{blue}{-4k^{10/3} + 24k^{4/3}}$
