Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter R - Review of Basic Concepts - R.6 Rational Exponents - R.6 Exercises - Page 64: 85

Answer

$\color{blue}{x^2-x}$

Work Step by Step

RECALL: $(a+b)(a-b)=a^2-b^2$ Use the formula above with $a=x$ and $b=x^{1/2}$ to obtain: $=x^2-(x^{1/2})^2$ Use the rule $(a^m)^n = a^{mn}$ to obtain: $=x^2 - x^{(1/2)\cdot 2} \\=x^2-x^1 \\=\color{blue}{x^2-x}$
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