Answer
$\frac{y}{y+2}$
Work Step by Step
Multiply $y$ to both the numerator and the denominator, we have $\frac{y-2}{y-\frac{4}{y}}=\frac{y-2}{y-\frac{4}{y}}\times\frac{y}{y}=\frac{y(y-2)}{y^2-4}=\frac{y(y-2)}{(y+2)(y-2)}=\frac{y}{y+2}$
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