Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter R - Review of Basic Concepts - Test - Page 86: 29

Answer

$ \frac{y}{x}$

Work Step by Step

$(\frac{x^{-2}y^{-1/3}}{x^{-5/3}y^{-2/3}})^3=(x^{(-2+5/3)}y^{(-1/3+2/3)})^3=(x^{(-1/3)}y^{(1/3)})^3=x^{-1}y=\frac{y}{x}$
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