Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 1 - Section 1.1 - Real Numbers - 1.1 Exercises - Page 10: 38

Answer

a.) True b.) True

Work Step by Step

a.) $\frac{7}{11}$ $\geq$ $\frac{8}{13}$ The Least Common Denominator of 11 and 13 = 143 (They are both prime numbers and only share multiples of each other) $\frac{91}{143}$ $\geq$ $\frac{88}{143}$ In terms of the same denominator, 91 is bigger than 88. True b.)-$\frac{3}{5}$ $\gt$ -$\frac{3}{4}$ The Least Common Denominator of 5 and 4 = 20 -$\frac{12}{20}$ $\gt$ -$\frac{15}{20}$ Since both numbers are negative, the number that is closer to 0 [-$\frac{12}{20}$]are bigger than the one that is farther away [-$\frac{15}{20}$] True
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