Answer
quadratic
x+1
$W^{2}-5W+6=0$
Work Step by Step
$(x+1)^2-5(x+1)+6=0$
Remember
Linear takes form of $ax+b=0$
quadratic takes form of $ax^{2}+bx+c=0$
so this is quadratic type
Set W=(x+1) [substitute (x+1) with W]
$W^2-5W+6=0$
Precalculus: Mathematics for Calculus, 7th Edition
by Stewart, James; Redlin, Lothar; Watson, Saleem
Published by
Brooks Cole
ISBN 10:
1305071751
ISBN 13:
978-1-30507-175-9
Chapter 1 - Section 1.5 - Equations - 1.5 Exercises - Page 56: 6
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