Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 1 - Section 1.5 - Equations - 1.5 Exercises - Page 56: 8

Answer

A. $\ square$ B. $\ 4x^2 + 4x + 1 = x + 1$

Work Step by Step

For letter A, the only way to eliminate said radical and solve this equation is to square both sides. Letter B, square both sides. Squaring the radical will leave "x+1," whereas the other side will become "4x^2 + 4x +1."
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.