Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 1 - Section 1.7 - Modeling with Equations - 1.7 Exercises - Page 78: 74

Answer

50mph

Work Step by Step

Person traveled at speed $x$ for 250 miles. And then traveled at speed $x+10$ for 360 miles. The entire trip took 11 hours. Solve for X. So lets make this a formula: $\frac{250}{x}+ \frac{360}{x+10} = 11$ We need a common denominator so our first fraction lets multiply by $\frac{x+10}{x+10}$ so we get: $\frac{250x+2500}{x^2 + 10x}+ \frac{360}{x+10} = 11$ Then to match, the second fraction we multiply by $\frac{x}{x}$ and we get: $\frac{250x+2500}{x^2 + 10x}+ \frac{360x}{x^2+10x} = 11$ Now multiply both sides by $x^2+10x$ then reduce to one side $250x + 2500 + 360x = 11x^2+110x$ $610x + 2500 = 11x^2 + 110x$ $610x = 11x^2 + 110x - 2500$ $0 = 11x^2 -500x - 2500$ Now we plug this into the quadratic formula: $x = \frac{500\frac{+}{-}\sqrt (-500^2-(4*11*-2500))}{2*11}$ $x = \frac{500\frac{+}{-}\sqrt (250000+110000)}{22}$ $x = \frac{500\frac{+}{-}\sqrt (360000)}{22}$ $x = \frac{500\frac{+}{-}\sqrt (360000)}{22}$ $x = \frac{500\frac{+}{-}1100}{22}$ So we get two answers from this. $50$ and $-27.2727$. This answer requires a positive number so we get 50. Let's confirm our answer: $\frac{250}{50} + \frac{360}{50+10} = 11$ $5 + 6 = 11$ $11 = 11$ Perfect!
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