Applied Statistics and Probability for Engineers, 6th Edition

Published by Wiley
ISBN 10: 1118539710
ISBN 13: 978-1-11853-971-2

Chapter 3 - Section 3-2 - Probability Distributions and Probability Mass Functions - Exercises - Page 70: 3-30

Answer

$P(X=0) = 0.001$ $P(X=1) = 0.068$ $P(X=2) = 0.931$

Work Step by Step

Let X = event that x number of parts meet specifications. For component A, probability of meeting specifications is 0.95, so the probability of defect is 1-0.95 = 0.05; and for component B, the probability of meeting specifications is 0.98 and so the probability of defect is 1-0.98 = 0.02. The probability mass function is given by the following: P(X=0) = Prob(x=0 parts meet specifications, both defective) = (0.02)(0.05) = 0.001 P(X=1) = Prob(x=1 part meets specifications, either A or B) = (0.95)(0.02)+(0.05)(0.98) = 0.068 P(X=2) = Prob(x=2, both parts meet specifications) = (0.98)(0.95) because they are independent = 0.931
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