Applied Statistics and Probability for Engineers, 6th Edition

Published by Wiley
ISBN 10: 1118539710
ISBN 13: 978-1-11853-971-2

Chapter 3 - Section 3-2 - Probability Distributions and Probability Mass Functions - Exercises - Page 70: 3-33

Answer

$$\begin{aligned} \\ f(1)=0.038, \\ f(2)=0.102,\\ f(3)=0.172, \\ f(4)=0.204, \\ f(5)=0.174,\\ f(6)=0.124, \\ f(7)=0.080, & \\ f(8)=0.036, &\\ f(9)=0.028, \\ f(10)=0.022, \\ f(15)=0.020, \end{aligned} $$

Work Step by Step

we can convert the percent to probability $$\begin{aligned} \\ f(1)=P(X=1)=3.8\times100=0.038, \\ f(2)=0.102,\\ f(3)=0.172, \\ f(4)=0.204, \\ f(5)=0.174,\\ f(6)=0.124, \\ f(7)=0.080, & \\ f(8)=0.036, &\\ f(9)=0.028, \\ f(10)=0.022, \\ f(15)=0.020, \end{aligned} $$
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