Answer
$f(x)=\left\{\begin{array}{ll}{0.005,} & {x=217} \\ {0.003,} & {x=218} \\ {0.045,} & {x=231} \\ {0.370,} & {x=255} \\ {0.151,} & {x=267} \\ {0.426,} & {x=317}\end{array}\right.$
Work Step by Step
X∈{217,218,231,255,267,317}, so
$P(X=217)=\frac{36}{7,726}=0.005$
$P(X=218)=\frac{26}{7,726}=0.003$
$P(X=231)=\frac{349}{7,726}=0.045$
$P(X=255)=\frac{1,515+1,343}{7,726}=0.370$
$P(X=267)=\frac{280+887}{7,726}=0.151$
$P(X=317)=\frac{3,290}{7,726}=0.426$
