Answer
$μ=1.57$,
$σ²=0.3111$
Work Step by Step
$\begin{aligned}μ= \mathbb{E}(X) &=0 \times 0.033+1 \times 0.364+2 \times 0.603=1.57\\ \mathbb{E}\left(X^{2}\right) &=0^{2} \times 0.033+1^{2} \times 0.364+2^{2} \times 0.603=2.776 \\σ²= \operatorname{Var}(X) &=\mathbb{E}\left(X^{2}\right)-\mathbb{E}(X)^{2}=0.3111 \end{aligned}$