Applied Statistics and Probability for Engineers, 6th Edition

Published by Wiley
ISBN 10: 1118539710
ISBN 13: 978-1-11853-971-2

Chapter 3 - Section 3-4 - Mean and Variance of a Discrete Random Variable - Exercises - Page 77: 3-64

Answer

$μ=2.937$, $σ²=0.064$

Work Step by Step

$μ=E(x)=∑xP(x)=0 \times 8 \times 10^{-6}+1 \times 0.00176+2 \times 0.0576+3 \times 0.94 \approx 2.937$ $\mathbb{E}\left(X^{2}\right)=0^{2} \times 8 \times 10^{-6}+1^{2} \times 0.00176+2^{2} \times 0.0576+3^{2} \times 0.94=8.69$ $σ²=\operatorname{Var}(X)=\mathbb{E}\left(X^{2}\right)-\mathbb{E}(X)^{2} \approx0.064$
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