Applied Statistics and Probability for Engineers, 6th Edition

Published by Wiley
ISBN 10: 1118539710
ISBN 13: 978-1-11853-971-2

Chapter 3 - Section 3-4 - Mean and Variance of a Discrete Random Variable - Exercises - Page 77: 3-57

Answer

μ=2, σ²=2

Work Step by Step

Given, P(x=0)=P(x=1)=P(x=2)=P(x=3)=P(x=4)=0.2, then, μ=E(x)=∑xP(x)=0×0.2+1×0.2+2×0.2+3×0.2+4×0.2=2, σ²=V(x)=∑x²P(x)-μ²=0²×0.2+1²×0.2+2²×0.2+3²×0.2+4²×0.2-2²=2
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